Integrate 16cos^2x
![Integrate 16cos^2x](integrate-16cos_2_x/step-01.gif)
To integrate 16cos^2x, also written as ∫16cos2x dx, 16cos squared x, 16cos^2(x), we start by using standard trig identities to to change the form.
![Using the Pythagorean trig identity.](integrate-16cos_2_x/step-02.gif)
We recall the Pythagorean trig identity and rearrange it for cos squared x.
![Using the double angle trig identity.](integrate-16cos_2_x/step-03.gif)
We recall the double angle trig identity and rearrange it for sin squared x.
![Making a new expression using trig substitution.](integrate-16cos_2_x/step-04.gif)
We substitute trig identity [2] into trig identity [1]. The substituted part is in brackets. We then simplify, and transpose for cos squared x.
![Integration of a new form.](integrate-16cos_2_x/step-05.gif)
Going back to our original integration problem, we can now rewrite it in a new form as shown on the LHS.
![Multiplying out 16 to simplify.](integrate-16cos_2_x/step-06.gif)
We can now multiply each term by 16 to simplify further.
![Integrating each term separately.](integrate-16cos_2_x/step-07.gif)
We can now integrate each term separately.
![Moving the constant multiplier outside.](integrate-16cos_2_x/step-08.gif)
We move the constant 8 outside the integral to simplify further. Then we focus on integrating the cos2x term as shown below.
![Integrating cos2x](integrate-16cos_2_x/step-09.gif)
Shown above is the answer for integrating cos2x. We can now substitute that part in our original integration problem.
![Original integration problem in new form.](integrate-16cos_2_x/step-10.gif)
This was the new form of our integration problem and we have the answer for the second term. The first term which is a constant 8 is simple to integrate.
![](integrate-16cos_2_x/step-11.gif)
Hence, we integrate the first term and substitute the solution for the second term.
![Final answer.](integrate-16cos_2_x/step-12.gif)
Hence, this is the final answer.