Integrate 8e^-2x

To integrate 8e^-2x, also written as ∫8e^-2x dx, we notice that "8" is a constant multiplier.

We bring the constant multiplier outside of the integral; hence, we get a simpler version that is the same thing.

We use this general rule for integrating an exponential.

Hence, the answer is this. The constant multiplier remains outside of the brackets.

We then simplify and remove the brackets.

Solved!