Integrate tan^23x
![Integrate tan^23x](integrate-tan_2_3x/step-01.gif)
To integrate tan^23x, also written as ∫tan23x dx, tan squared 3x, (tan3x)^2, and tan^2(3x), we start by utilising trig identities to change the form.
![Trig Identity](integrate-tan_2_3x/step-02.gif)
We recall the Pythagorean trig identity and adjust it by multiplying the angles by 3.
![Trig identity](integrate-tan_2_3x/step-03.gif)
We then rearrange it for sin23x.
![Divide throughout by cos^23x](integrate-tan_2_3x/step-04.gif)
We now divide throughout by cos23x.
![New expression for tan^23x](integrate-tan_2_3x/step-05.gif)
As you can see, the LHS looks like our integration problem.
![secx=1/cosx](integrate-tan_2_3x/step-06.gif)
We recall this simple trig identity for secx.
![Multiplying the angles, and squaring the terms.](integrate-tan_2_3x/step-07.gif)
We adjust the identity by multiplying the angles by 3, and squaring both sides.
![expression for tan^23x dx](integrate-tan_2_3x/step-08.gif)
We substitute expression [2] into expression [1] to get a new expression with sec23x.
![New form of integration](integrate-tan_2_3x/step-09.gif)
Hence, we can rewrite our original integration problem, as shown above. The RHS shows a different form that means the same thing.
![Standard proof](integrate-tan_2_3x/step-10.gif)
We recall a standard proof from formula books. Back in my days, I did "A" levels and the formula booklet had one of these.
![Integral of sec^23x dx](integrate-tan_2_3x/step-11.gif)
Therefore, in our case, this is the result for the first term on the RHS.
![Final Answer](integrate-tan_2_3x/step-12.gif)
Hence, this is the final answer, and C is the integration constant.