Solve 16x^2-8x+1=0

To solve 16x^2-8x+1=0 (also written as 16x²-8x+1=0), we notice that it is already in the standard form ax²+bx+c=0.

These are the coefficients, where a=16, b=-8, and c=1.

We now substitute the coefficients into the quadratic equation formula and simplify. Notice that since coefficient b is a negative number, - (-8) becomes +8. Students trip here, so you should sort that part out at the very beginning to avoid making any errors.

There is only one solution because the discriminant part (b²-4×a×c) is zero.