Solve 15x^2+7x-2=0
To solve 15x^2+7x-2=0 (also written as 15x²+7x-2=0), we notice that it is already in the standard form ax²+bx+c=0.
These are the coefficients, where a=15, b=7, and c=-2.
We now substitute the coefficients into the quadratic equation formula and simplify.
This is the first solution.
This is the second solution.